怎样计算ccd摄像头的采集点数

cys179 · 发表于 2009-3-11 17:54:02

计算采集点数？
你要怎么计算啊？？？
估计你可能还没有搞清楚摄像头的时序问题！
点数在你采集的时候是要用你的程序来试的，这和你的程序的效率有很大关系。c估计无法计算。只有用实际的采集来的看了。汇编估计可以，你好好在看看摄像头的时序吧。我刚开始的时候也想到过你的这个问题。
cys179@gmail.com 可以练习我。

补充内容 (2015-4-23 09:36):
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whut_wj · 发表于 2009-3-11 19:28:30

配合示波器看,

边荒 · 发表于 2009-3-11 20:47:14

C:\Documents and Settings\You chuanjiang\桌面\test0.7.25

边荒 · 发表于 2009-3-11 20:48:34

弄错了，呵呵
#include <hidef.h>    /* common defines and macros */
#include <mc9s12dg128.h>    /* derivative information */
#pragma LINK_INFO DERIVATIVE "mc9s12dg128b"
unsigned char imagin[40][70];
unsigned char guiji[40];
unsigned int sd_z[4]={450,500,550,600},z_sd,w_sd;
unsigned int sd_w[4]={280,300,310,320};
unsigned char jsd_z[4]={30,20,15,5},z_jsd,w_jsd;
unsigned char jsd_w[2]={30,20};
char i=0,j=0,k=0,complete=2;
unsigned char go,speed,cnt,flag_j,cnt2=210,cnt3=0;
int pingjun;
unsigned char *p;
unsigned int *addr;
//*******************图像分析函数****************************
void fenxi(void) {
  unsigned char ii,jj,kk,buf2=0,buf3=3,sum=0;
  char buf;
  int sum1=0,sum2=0;
//cnt2=0;
  /* for(ii=10;ii<60;ii++) {
sum1=0;
kk=0;
for(jj=20;jj<40;jj++) {
   if((imagin[jj][ii]<55)&&(imagin[jj][ii-1]<55)){
      kk++;
      sum1+=jj;
   }
}
if(kk)
   hx[ii]=(char)(sum1/kk);
else hx[ii]=0;
  }
  buf2=0;
  kk=0;
  for(ii=11;ii<60;ii++) {
if(hx[ii]){
   //if(buf3>10)
      //buf3=0;
   buf=hx[ii]-hx[ii-1];
   if((buf<2)&&(buf>(-2))&&(buf3>2))
      kk++;
   else{
   if(kk>4) {
      buf3=0;
      kk=0;
      if(kk<20)
      buf2++;
      }
   }
   //else if(kk>8)
}
else {
   if(kk>4) {
      buf3=0;
      buf2++;
   }
   buf3++;
   kk=0;
}
  }
  if(kk>4)
buf2++;
  if(buf2==2){
PORTK|=0x04;
cnt3++;
if(cnt3>0){
   cnt3=0;
   if((cnt2>200)&&go){
      cnt2=0;
      flag_q++;
   }
   if(flag_q>1){
      PWMDTY0=0;
      speed=0;
      go=0;
      PORTK&=0xfe;
      flag_q=0;
   }
}
  }
  else {
PORTK&=0xfb;
cnt3=0;
  }*/
  jj=39;
  kk=0;
  there:p=&imagin[jj][0];
  for(ii=0;ii<70;ii++){
   if(*(p++)<50) {
      kk++;
   }
   else {
      if(kk>13) {
      pingjun=0;
      return;
      }
      else if(kk>3)break;
      else
      kk=0;
   }
}
if(kk<2){
   if(jj>35)jj--;
   else return;
   goto there;
}
guiji[jj]=ii-1;
buf=ii-7;
if(buf<0)buf=0;
else if(buf>56)buf=56;
kk=0;
buf3=jj-2;
jj--;
  for(;jj>18;jj--){
sum=0;
p=&imagin[jj][buf];
kk=0;
buf2=0;
for(ii=0;ii<14;ii++){
   if((*(p++)<60)&&(*p<60)) {
      kk++;
      sum+=ii;
   }
}
if(kk>0) {
   guiji[jj]=sum/kk+buf;
}
else {
   if(guiji[jj+1]>65){
      pingjun=140;
      flag_j=1;
      goto here2;
   }
   else if(guiji[jj+1]<10){
      pingjun=-140;
      flag_j=1;
      goto here2;
   }
   if(jj<38)
      guiji[jj]=2*guiji[jj+1]-guiji[jj+2];
   else guiji[jj]=guiji[jj+1];
}
//if(guiji[jj]>(guiji[jj+1]+1))
   buf=guiji[jj]-7;                //
//else if((guiji[jj]+1)<guiji[jj+1])
   // buf=guiji[jj]-13;
// else buf=guiji[jj]-7;
if(buf<0)buf=0;
else if(buf>56)buf=56;
  }
  if(buf>50)buf=50;
  for(jj=18;jj>0;jj--){
buf2=0;
p=&imagin[jj][buf];
kk=0;
for(ii=0;ii<20;ii++){
   if(*p<65) {
      kk++;
   }
   else {
      if(kk>0)break;
      else{
      buf2=ii;
      kk=0;
      }
   }
   p++;
}
if(kk<1) {
   guiji[jj]=guiji[jj+1];
   continue;
}
else{
   buf2+=buf;
   buf+=ii;
   if(buf<guiji[jj+1])
      guiji[jj]=buf2;
   else
      guiji[jj]=buf;
}
buf=guiji[jj]-10;
if(buf<0)buf=0;
else if(buf>50)buf=50;
  }
  //求平均偏移量//
  flag_j=0;
  for(jj=3;jj<7;jj++){
if((guiji[jj]>60)||(guiji[jj]<10))
   flag_j=1;
  }
  for(jj=8;jj<12;jj++){
sum1+=guiji[jj];
if((guiji[jj]>60)||(guiji[jj]<10))
   flag_j=1;
  }
  sum1/=4;
  for(jj=27;jj<30;jj++){
sum2+=guiji[jj];
  }
  sum2/=3;
  pingjun=5*(sum1-35)-2*(sum1-sum2);
  //pingjun=(sum2-35)*4;
  if(pingjun>140)pingjun=140;
  if(pingjun<(-140))pingjun=-140;
  here2:
  if(flag_j)PORTK|=0x08;
  else PORTK&=0xf7;
}
//*****eeprom初始化*************************
void init_eeprom(void) {
  ECLKDIV=0x15;
  ECNFG=0;
  while(ECLKDIV_EDIVLD==0);
}
//*****写eeprom*************************
char write_eeprom(unsigned int dat) {
  while(ESTAT_CBEIF==0);
  *addr=dat;
  ECMD=0x60;
  ESTAT=0x80;
  while(ESTAT_CCIF==0);
  if(ESTAT_ACCERR)return 0;
  return 1;
}
//*****PWM初始化*************************
void init_pwm(void) {
  PWME=0;
  PWMPRCLK=0x53;
  PWMSCLA=25;
  PWMSCLB=50;
  PWMCLK=0x03;
  PWMDTY0=0;
  PWMPER0=100;
  PWMDTY67=1503;
  PWMPER67=20000;
  PWMPOL=0x80;
  PWMCAE=0x00;
  PWMCTL=0x80;
  PWME=0x81;
}
//****************************************
void main(void) {
  char flag=0;
  int buf1;
  INITEE = 0x61;  /* lock EEPROM block to end at 0x0fff */
  CLKSEL &= 0x7F;
  REFDV = 1;
  SYNR = 3;
  while(!(CRGFLG&0x08));
  CLKSEL |= 0x80;
  init_eeprom();
  addr=(unsigned int *)0x6002;
  DDRK|=0x2f;    //portk的低四位做能为输出
  TSCR1=0x80;
  TSCR2=0x83;
  PACTL=0x40;
  TCNT=0x00;
  TIOS=0x00;
  TCTL4=0x55;
  TIE=0x06;
  DLYCT=0x00;
  INTCR=0xC0; //VSYNC下降沿触发
  DDRH&=0xfe;
  PPSH=0x01; //HREF上升沿触发
  PIEH=0x01;
  DDRA=0x00;
  SCI0CR2=0x0c;
  SCI0BDH=0x00;
  SCI0BDL=104;       //波特率=19200 208;
  DDRM=0x00;    //拨码开关设定为输入
  PERM=0xff;    //上下拉使能
  PPSM=0x00;    //上拉
  init_pwm();
  //if(*addr==1){
go=1;
PORTK|=0x01;
  //}
  buf1=PTM;
  z_sd=sd_z[buf1&0x03];
  buf1>>=2;
  z_jsd=jsd_z[buf1&0x03];
  buf1>>=2;
  w_sd=sd_w[buf1&0x03];
  buf1>>=1;
  w_jsd=jsd_w[buf1&0x01];
  //PLLCTL=0xf3;
  //COPCTL=0x05;
  EnableInterrupts;
for(;;) {
//ARMCOP=0X55;
  if(complete==1) {
DisableInterrupts;
if(flag==1){
   for(i=0;i<40;i++){                //////
   while(!(SCI0SR1&0x80));
   SCI0DRL=0;
   for(j=0;j<70;j++) {
      while(!(SCI0SR1&0x80));
      SCI0DRL=imagin[i][j];
   }
}
while(!(SCI0SR1&0x80));
SCI0DRL=0;
while(!(SCI0SR1&0x80));
SCI0DRL=0;
}
//ARMCOP=0XAA;
fenxi();
   buf1=1503-pingjun;
   PWMDTY67=buf1;
EnableInterrupts;
flag=0;
complete=2;
  }
  if(SCI0SR1&0x20) {
if(SCI0DRL==48) {
   flag=1;
   complete=2;
}
  }
}
}

//*********************************************
#pragma CODE_SEG NON_BANKED

void interrupt  VSYNC_ISR(void) //场信号中断
{
DisableInterrupts;  //关中断
if(complete==2) {
  i=0;
  complete=0;
  k=0;
  p=&imagin[0][0];
  }
}
void interrupt  HREF_PH0(void) { //行信号中断
unsigned char jj;
DisableInterrupts;  //关中断
  if(complete==0) {
if(k>6) {
   for(jj=0;jj<70;jj++){
      k=0;
      *(p++)= PORTA;
   }
   i++;
   if(i>39) complete=1;
}
k++;
  }
PIFH=0x01;

}
//******************************************************
void interrupt  Timer(void) {       //时间中断，调速
unsigned int buf;
int such;
  DisableInterrupts;  //关中断
  TCNT=0;
  buf=PACN32;
  PACN32=0;
  if(cnt2<210)cnt2++;
  if(cnt)
cnt--;
  else {
PORTK^=0x02;
if(go==1){
   if(flag_j==0){
      PORTK&=0xf7;
      such=buf-z_sd;
      if(such<0){
      such/=z_jsd;
      }
      else such/=30;
   }
   else {
   PORTK|=0x08;
   if(buf>420){
      cnt=4;
      PORTK|=0x20;
      PWMDTY0=65;
      goto out;
   }
   if(buf>400){
      cnt=4;
      PORTK|=0x20;
      PWMDTY0=60;
      goto out;
   }
   if(buf>370){
      cnt=3;
      PORTK|=0x20;
      PWMDTY0=60;
      goto out;
   }
   such=buf-w_sd;
   if(such>0)
      such/=30;
   else{
      such/=w_jsd;
   }
   }
   PORTK&=0xdf;
   if(speed>such)speed-=such;
   else speed=0;
   if(speed>95)speed=95;
   PWMDTY0=speed;
}
  }
  out: TFLG2=0x80;
}
//******************************************************
void interrupt IC1_ISR(void) {
DisableInterrupts;  //关中断    C
  TFLG1=0x02;
  PORTK|=0x01;
  go=1;
  while(write_eeprom(1)==0);
}
void interrupt IC2_ISR(void) {
DisableInterrupts;  //关中断    B
  TFLG1=0x04;
  PORTK&=0xfe;
  go=0;
  PWMDTY0=0;
  speed=0;
  while(write_eeprom(0)==0);
}试试这个程序

cys179 · 发表于 2009-3-14 15:40:19

大哥也不给个注释。把人往死里看啊

rocky · 发表于 2009-3-15 18:09:58

好好了解ccd的工作原理后，你就会了，最直观的方法就是用示波器看时序图，强烈建议

xiaopang1989 · 发表于 2009-4-6 16:24:16

这程序可以直接仿真吧，看了一下，感觉有的循环太罗嗦，可以简练点的。

草竹 · 发表于 2009-4-6 20:31:56

大哥也不给个注释。把人往死里看啊
cys179 发表于 2009-3-14 15:40

sail0695 · 发表于 2009-5-15 10:23:54

太长了把。。。。。。。。。。

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