智能车制作
标题:
单片机超频是与硬件系统的外部晶振源有关的吧
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作者:
junjianjunjian
时间:
2010-4-17 19:13
标题:
单片机超频是与硬件系统的外部晶振源有关的吧
很多人都在找相关超频的代码,但是我想,这个还与自身的外部晶振源有关的吧,比如说,我的外部晶振是16M的,那么,我还能用PLL超到80M吗??
作者:
王怀玉
时间:
2010-4-17 19:13
超频代码
#include <hidef.h> /* common defines and macros */
#include <MC9S12XS128.h> /* derivative information */
#pragma LINK_INFO DERIVATIVE "mc9s12xs128"
void delayms(int ms)
{
int ii,jj;
if (ms<1) ms=1;
for(ii=0;ii<ms;ii++)
for(jj=0;jj<3338;jj++); //40MHz--1ms
}
void SetBusCLK_16M(void)
{
CLKSEL=0X00; // disengage PLL to system
PLLCTL_PLLON=1; // turn on PLL
SYNR=0x00 | 0x01; // VCOFRQ[7:6];SYNDIV[5:0]
// fVCO= 2*fOSC*(SYNDIV + 1)/(REFDIV + 1)
// fPLL= fVCO/(2 × POSTDIV)
// fBUS= fPLL/2
// VCOCLK Frequency Ranges VCOFRQ[7:6]
// 32MHz <= fVCO <= 48MHz 00
// 48MHz < fVCO <= 80MHz 01
// Reserved 10
// 80MHz < fVCO <= 120MHz 11
REFDV=0x80 | 0x01; // REFFRQ[7:6];REFDIV[5:0]
// fREF=fOSC/(REFDIV + 1)
// REFCLK Frequency Ranges REFFRQ[7:6]
// 1MHz <= fREF <= 2MHz 00
// 2MHz < fREF <= 6MHz 01
// 6MHz < fREF <= 12MHz 10
// fREF > 12MHz 11
// pllclock=2*osc*(1+SYNR)/(1+REFDV)=32MHz;
POSTDIV=0x00; // 4:0, fPLL= fVCO/(2xPOSTDIV)
// If POSTDIV = $00 then fPLL is identical to fVCO (divide by one).
_asm(nop); // BUS CLOCK=16M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_32M(void)
{
CLKSEL=0X00; // disengage PLL to system
PLLCTL_PLLON=1; // turn on PLL
SYNR =0x40 | 0x03; // pllclock=2*osc*(1+SYNR)/(1+REFDV)=64MHz;
REFDV=0x80 | 0x01;
POSTDIV=0x00;
_asm(nop); // BUS CLOCK=32M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_40M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x04;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=80MHz;
_asm(nop); //BUS CLOCK=40M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_48M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x05;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=96MHz;
_asm(nop); //BUS CLOCK=48M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_64M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x07;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=128MHz;
_asm(nop); //BUS CLOCK=64M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_80M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x09;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=160MHz;
_asm(nop); //BUS CLOCK=80M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_88M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x0a;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=176MHz;
_asm(nop); //BUS CLOCK=88M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_96M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x0b;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=192MHz;
_asm(nop); //BUS CLOCK=96M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_104M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x0c;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=208MHz;
_asm(nop); //BUS CLOCK=104M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
void SetBusCLK_120M(void)
{
CLKSEL=0X00; //disengage PLL to system
PLLCTL_PLLON=1; //turn on PLL
SYNR =0xc0 | 0x0d;
REFDV=0x80 | 0x01;
POSTDIV=0x00; //pllclock=2*osc*(1+SYNR)/(1+REFDV)=240MHz;
_asm(nop); //BUS CLOCK=120M
_asm(nop);
while(!(CRGFLG_LOCK==1)); //when pll is steady ,then use it;
CLKSEL_PLLSEL =1; //engage PLL to system;
}
作者:
我的A计划
时间:
2010-4-17 19:50
可以的,我们的另外一队就超到了80M!
作者:
我的A计划
时间:
2010-4-17 19:51
不信你超频,但是可能会死机,就是单片机死机
作者:
junjianjunjian
时间:
2010-4-17 21:06
回复
3#
我的A计划
但是PLL计算的时候,公式里有个OSC,这个值是什么呢
作者:
王怀玉
时间:
2010-4-18 19:29
如果你的板子可以超频到96M建议使用80m,一次类推
作者:
junjianjunjian
时间:
2010-4-19 23:31
如果你的板子可以超频到96M建议使用80m,一次类推
王怀玉 发表于 2010-4-18 19:29
再菜菜的问一下,计算PLL频率的时候,公式里用到的OSC 是系统板上的外部晶振大小吗??
作者:
王怀玉
时间:
2010-4-20 18:52
回复
7#
junjianjunjian
不清楚
作者:
qijitao
时间:
2010-5-8 14:41
学习了
作者:
robotong
时间:
2010-6-29 07:57
不懂
作者:
shuxinxiaozi
时间:
2010-7-9 16:57
学习了。不过确实没搞懂osc是怎么计算的?
作者:
阿尔卑斯一号
时间:
2013-4-12 18:32
请问怎样侧超频呢?
作者:
阿尔卑斯一号
时间:
2013-4-12 18:33
请问怎么测超频呢?
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